Tel - Protocol and making phone call with access code.

 

     making a phone call with tel protocol

If we want to launch a phone app from our app we need to implement the "tel" protocol in iOS. iOS 10.3 or later versions giving an alert to the users before a call. if we use "teleprompt" in our app, the app doesn't submit in Appstore. 

How do we make a phone call from our App?

The syntax for this,

    [[UIApplication sharedApplication]  openURL:[NSURL URLWithString:@"tel://15415551234"]];

[[UIApplication sharedApplication]openURL:[NSURL URLWithString:@"tel:15415551234"]];

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"tel:1-541-555-1234"]];

How to make a call with access code?

    If we want to make an call with access code we need to give "," before the access code. 

for example 

    34758453454,,12345,,,345#

The "," stands for a small delay or pause. This "," makes a space for the IVR sounds.

I just collect the details for make a call with access code. 

Happy codeing....!